Wednesday, 30 June 2010

Example of Permutations in C++

Example of how you can let the Algorithm class generate permutations of String



//Program tested on Microsoft Visual Studio 2008 - Zahid Ghadialy
#include<iostream>
#include<algorithm>
#include<string>
#include<vector>

using namespace
std;

int
main()
{

string someString="ABC";
vector<string> someVector;

someVector.push_back(someString);

string::iterator itBegin = someString.begin();
string::iterator itEnd = someString.end();

while
(next_permutation(itBegin, itEnd)) //std::next_permutation defined in algorithm
{
someVector.push_back(string(itBegin, itEnd));
}

copy(someVector.begin(), someVector.end(), ostream_iterator<string>(cout, "\n"));

return
0;
}



The output is as follows:


Wednesday, 23 June 2010

Challenging problem to test your 'for loop' basics

While scouting through the web I came across this fun puzzle:

In the following code:


#include<iostream>

using namespace
std;

int
main()
{

int
i, n = 20;
for
(i=0; i<n; i--)
{

cout << "x" << endl;
}


return
0;
}




by changing only ONE character in the above code, meaning you cannot change 20 to 31, because you will have changed two characters, you can change 20 to 21, because you only changed the 0, do the following:

find 3 ways to make the above code print x 20 times (by changing only one character).


Give it a try, if you can do it then look at the answer below.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
The first one should be simple:
i-- becomes n--
.
.
.
.
.
.
.
I guess this is the second one you got
i<n becomes i+n
.
.
.
.
.
.
.
.
.
.
The third one which is tricky, In fact there are two similar solutions is:

i<n becomes, -i<n,
i
<n becomes, ~i<n

remember BODMAS


Wednesday, 16 June 2010

Forwarding functions

Sometimes it is required to seperate the interface from implementation and 'forwarding functions' can be useful. The interface class can forward the work to the implementation keeping the interface clean and minimal.

The following is a simple example where function f() forwards its work to function g():



//g.h
#pragma once

bool
g(int x)
{

if
(x%2 == 0)
return
true;
else
return
false;
}



//f.h
#pragma once

bool
f(int x);


//f.cpp
#include<iostream>

#include "f.h"
#include "g.h"

bool
f(int x)
{

return
g(x);
}



//main.cpp
//Program tested on Microsoft Visual Studio 2008 - Zahid Ghadialy
#include<iostream>

#include "f.h"

using namespace
std;

int
main()
{

if
(f(20))
cout<<"TRUE"<<endl;
else

cout<<"FALSE"<<endl;

return
0;
}





There are couple of things to keep in mind when writing them. See here.

You can read more about seperating Interface and Implementation here.

Wednesday, 9 June 2010

Simulating 'break all' in C++

Sometimes your program is inside multiple loops when it meets a certain criteria and all you want to do is to break out from all the loops. Some programming languages allow 'break all' statements while most of them dont.

In Java there is a nice little feature of using a label on the outermost loop and then you can say inside 'break label' to break from the outermost loop. This is shown in the example below



String valueFromObj2 = null;
String valueFromObj4 = null;
OUTERMOST: for(Object1 object1: objects){
for(Object2 object2: object1){
//I get some value from object2
valueFromObj2 = object2.getSomeValue();
for(Object3 object3 : object2){
for(Object4 object4: object3){
//Finally I get some value from Object4.
valueFromObj4 = object4.getSomeValue();
//Compare with valueFromObj2 to decide either to break all the foreach loop
if( compareTwoVariable(valueFromObj2, valueFromObj4 )) {
break OUTERMOST;
}
}//fourth loop ends here
}//third loop ends here
}//second loop ends here
}//first loop ends here



The important thing to remember is this is not available in C++.

Another way of doing 'break all' is to have a 'flag' in each of the loop as well like:

while ( condition && !flag)

Then inside the nth loop set the flag to true and break. All the the loops will exit. This is a good approach and is widely used.

I prefer using another approach using the goto statement. A lot of C++ people hate goto and think its pure evil but I dont think its always that bad. Also see this. Example as follows:





//Program tested on Microsoft Visual Studio 2008 - Zahid Ghadialy
//Example of simulating break all in C++
#include<iostream>

using namespace
std;

int
main()
{


cout << "Entering the nested loop" << endl;
for
(int loop1 = 0; loop1 < 4; loop1++)
{

cout<<"Loop1 : " << loop1 << endl;
for
(int loop2 = 0; loop2 < 4; loop2++)
{

cout<<"Loop2 : " << loop2 << endl;
for
(int loop3 = 0; loop3 < 4; loop3++)
{

cout<<"Loop3 : " << loop3 << endl;
if
(loop3 == 3 && loop2 == 2 && loop1 == 1)
{

goto
SOMELABEL;
}
}
}
}

SOMELABEL:
cout << "Exiting the nested loop" << endl;

return
0;
}







The output is as follows:


Wednesday, 2 June 2010

Class initialisation and constructors

There is often lots of confusion with regards to class initialisation. People may forget to take care while using default constructors and copy constructors. Here is a simple example that tries to explain lots of concepts.





//Program tested on Microsoft Visual Studio 2008 - Zahid Ghadialy
//This program gives an example of constructors and initialisations

#include<iostream>

using namespace
std;

//Example of a class
class someClass1
{

public
:
//implicit default constructor
int x;
int
*y;
};


//Example of a class with constructor
class someClass2
{

public
:
someClass2(const someClass2& xyz)
{

cout<<"** copy constructor called"<<endl;
x = xyz.x;
y = new int(*xyz.y);
}

//default constructor will have to be explicitly defined
someClass2() {};
//overloading operator '='
const someClass2& operator = (const someClass2& xyz)
{

cout<<"** operator '=' called"<<endl;
x = xyz.x;
y = new int(*xyz.y);
return
*this;
}

int
x;
int
*y;
};


int
main()
{

someClass1 a; //Default initialisation
a.x = 1234;
a.y = new int(6789);

cout<<"someClass1: a.x = "<<a.x<<" a.y( " <<a.y<< " ) = "<<*(a.y)<<endl;

someClass1 b = a; //Copy Initialisation

cout<<"someClass1: b.x = "<<b.x<<" b.y( " <<b.y<< " ) = "<<*(b.y)<<endl;

someClass1 c(a); //Direct Initialisation

cout<<"someClass1: c.x = "<<c.x<<" c.y( " <<c.y<< " ) = "<<*(c.y)<<endl;

//Calling default constructor
someClass2 aa;
aa.x = 2468;
aa.y = new int(3579);

cout<<"someClass2: aa.x = "<<aa.x<<" aa.y( " <<aa.y<< " ) = "<<*(aa.y)<<endl;

//calling copy constructor
someClass2 bb = aa; //Copy Initialisation - note copy constructor will be called

cout<<"someClass2: bb.x = "<<bb.x<<" bb.y( " <<bb.y<< " ) = "<<*(bb.y)<<endl;

//calling copy constructor
someClass2 cc(aa); //Direct Initialisation - note copy constructor called in this case as well

cout<<"someClass2: cc.x = "<<cc.x<<" cc.y( " <<cc.y<< " ) = "<<*(cc.y)<<endl;

someClass2 dd;
//calling operator =
dd = aa;

cout<<"someClass2: dd.x = "<<dd.x<<" dd.y( " <<dd.y<< " ) = "<<*(dd.y)<<endl;

return
0;
}







The output is as follows:

There are certain things worth noting in the above example:
  • In case of someClass1, since only the default constructor is used, the same pointer is used for y in all the cases. This can cause serious problems in the code if one of the classes delete the memory pointed by y for class someClass1. This problem is not present in someClass2
  • If any constructor is defined, it becomes necessary to define the default constructor. You can make sure that nobody uses default constructor in case of someClass2 by making it private (I havent done that because I wanted to show operator =)
  • As you can see in case of variable cc, copy constructor would always be called instead of operator =.
  • operator = would only be called in case of assignment. This is a common mistake.
  • In the code above, cc(aa) is better than using bb = aa even though the results are the same. The main advantage being that it will avoid confusion with operator '=' if its overloaded for a novice and the constructor can be overloaded to take more than one input in future.